Go Back   Naruto & Bleach Mania Forums > General Discussion > General Discussion & News
User CP Rules & Info Arcade Gallery

http://www.narutomania.com/forums/New Month, New Problems
For these forums to remain up we need $480 within 7 days. Please donate HERE We need this amount no matter what to keep this website up. Thank you for your support.

Reply
 
Thread Tools
Old 21-12-2007, 05:17 AM   #1001
Akatsuki
 
Ice(v)an's Avatar


Join Date: Nov 2004
Location: Urahara Store
Posts: 9,395
My Mood:
Rep Power: 36
Ice(v)an has a brilliant futureIce(v)an has a brilliant futureIce(v)an has a brilliant futureIce(v)an has a brilliant future

Basic Bronze 
Total Awards: 1

Default Re: Homework Help v1.3

I'm having some trouble, finding some sites, that gives information that

relates Binomial Coefficients to statistics or

Pascal Triangle to the fibonacci numbers.
__________________



thanks to Tom, ~Mrge and Simonarturo, EE
Ice(v)an is online now   Reply With Quote
Old 21-12-2007, 11:17 AM   #1002
ANBU
 
Magnum's Avatar


Join Date: Aug 2007
Location: Have to ask my mom
Posts: 1,925
My Mood:
Rep Power: 10
Magnum is a glorious beacon of light

Basic Gold 
Total Awards: 1

Default Re: Homework Help v1.3

Pascal Triangle to the fibonacci numbers.
This is a pretty nice site.Fibonacci numbers and the Pascal triangle
__________________
Magnum is offline   Reply With Quote
Old 31-12-2007, 08:57 AM   #1003
o({})o


Join Date: Nov 2006
Posts: 98
My Mood:
Rep Power: 0
]MpC[hebe is an unknown quantity at this point
Default Re: Homework Help v1.3

Quote:
Originally Posted by Ice(v)an View Post
I'm having some trouble, finding some sites, that gives information that

relates Binomial Coefficients to statistics or

Pascal Triangle to the fibonacci numbers.
Not sure if you still needed help with this, but if you look up the Binomial Theorem in wikipedia, I'm sure you'll find plenty of reason that binomial coefficients are related to statistics.
__________________
This is my account for use on public computers.
Please do not PM this account unless you have good reason to believe that I will not be on my main account.
]MpC[hebe is offline   Reply With Quote
Old 03-01-2008, 08:24 PM   #1004
Hunter-nin
 
DeathGuiseX's Avatar


Join Date: Feb 2005
Location: East Side, NERV
Posts: 2,390
My Mood:
Rep Power: 31
DeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond repute
Send a message via AIM to DeathGuiseX
Default Re: Homework Help v1.3

Can someone help me with integration? we have to integrate sin x/ cos x dx, or also written as int. tanx dx.
The only other info the teacher gave us is that int. 1/u du = ln |u| + c and that we are using substitution. This may be a simple integration problem, but I was just introduced to this whole thing.
__________________
DeathGuiseX is offline   Reply With Quote
Old 04-01-2008, 12:55 AM   #1005
Genin


Join Date: Oct 2005
Posts: 75
Rep Power: 0
ahme has much to be proud ofahme has much to be proud ofahme has much to be proud of

Basic Bronze 
Total Awards: 1

Default Re: Homework Help v1.3

Just take u = cos x and go from there.
One trick to solve integration in the form of coefficients is to see if the numerator is the denominator's derivative or the denominator's derivative multiplied by a constant.
Well here we have the derivative of cos x which is - sin x. Bingo! blindly take the u = cos x and make the substitution. u = cos x then du = - sin x dx thus sin x / cos x dx = 1 / u . -du

Now, given the hint you instructor gave, it should be very easy to do the integral.
ahme is offline   Reply With Quote
Old 04-01-2008, 01:42 AM   #1006
Hunter-nin
 
DeathGuiseX's Avatar


Join Date: Feb 2005
Location: East Side, NERV
Posts: 2,390
My Mood:
Rep Power: 31
DeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond repute
Send a message via AIM to DeathGuiseX
Default Re: Homework Help v1.3

^Thanks, i got the answer as -ln |cos x| + c, but someone else said that they got -ln |sec x| + c. I looked it up and found the secant answer, how did you get that?
__________________
DeathGuiseX is offline   Reply With Quote
Old 04-01-2008, 02:10 AM   #1007
Life = Sex + Guns
 
Denny Crane's Avatar


Join Date: Oct 2004
Location: Red Light District
Posts: 21,981
My Mood:
Rep Power: 101
Denny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond reputeDenny Crane has a reputation beyond repute

Basic Bronze High Silver Award Basic Gold Basic Silver Intermediate Gold Award 
Total Awards: 5

Default Re: Homework Help v1.3

here is the answer
Integral tan(x)
__________________

Denny Crane is online now   Reply With Quote
Old 04-01-2008, 02:14 AM   #1008
Genin


Join Date: Oct 2005
Posts: 75
Rep Power: 0
ahme has much to be proud ofahme has much to be proud ofahme has much to be proud of

Basic Bronze 
Total Awards: 1

Default Re: Homework Help v1.3

That goes to the properties of logarithm.
ln x^y = y * ln x
thus, -ln |cos x| = ln | (cos x)^-1 | = ln |sec x|

note that it is positive and not negative if the sec is used
ahme is offline   Reply With Quote
Old 05-01-2008, 10:17 PM   #1009
ANBU
 
Jeaxz's Avatar


Join Date: Nov 2004
Posts: 1,009
Rep Power: 18
Jeaxz is a jewel in the rough
Default Re: Homework Help v1.3

Hey, guys, i was wondering if anyone know any easy autobiography and it has to be short. Cause i only have 5 days to work.
__________________



OH NO poor 360 :(

Jeaxz is offline   Reply With Quote
Old 06-01-2008, 12:24 AM   #1010
the Brown
 
4thseal's Avatar
Join Date: Apr 2007
Location: Never separate me from these stars...
Posts: 11,138
My Mood:
Rep Power: 59
4thseal has disabled reputation

High Gold Award 
Total Awards: 1

Send a message via AIM to 4thseal Send a message via MSN to 4thseal
Default Re: Homework Help v1.3

Don't know your deffinition of short, but here's a pretty short, famous, one that you can do a lot with:

Frederick Douglass: Narrative of the Life of Frederick Douglass, An American Slave

^that's the ebook for Frederick Dougleass' autobiography. It's a good read, so check it out.

Some more information of Frederick Douglass:

Frederick Douglass - Frederick Douglass Biography
__________________

Persistency is a fool's best asset
Exposed #15: Read & Comment


Last edited by 4thseal; 06-01-2008 at 12:25 AM.
4thseal is offline   Reply With Quote
Old 06-01-2008, 01:27 AM   #1011
ANBU
 
Jeaxz's Avatar


Join Date: Nov 2004
Posts: 1,009
Rep Power: 18
Jeaxz is a jewel in the rough
Default Re: Homework Help v1.3

yoo, thanks again man. Once again you save me ass. Thanks man apperciate it.
__________________



OH NO poor 360 :(

Jeaxz is offline   Reply With Quote
Old 08-01-2008, 11:34 AM   #1012
Hunter-nin
 
kafukai's Avatar


Join Date: Feb 2007
Location: Terra Niuiu, Moon(Earth)
Posts: 2,810
My Mood:
Rep Power: 20
kafukai has a brilliant futurekafukai has a brilliant futurekafukai has a brilliant future
Default Re: Homework Help v1.3

Quote:
Originally Posted by DeathGuiseX View Post
2. In which of the following substances is hydrogen bonding present? (can be 2, 3, or all answers) CH3NH2 , HOCl, NCl3, NH4Br
I really want to answer about all of your questions, but my english isn't so good and I'm not know the english terms.

The N(Nitrogen - 3.0),O(Oxygen - 3.5),F(Fluorine - 4.0) elements got the higher electronegativity so they allways(with H) got the biggest and strongest hydrogen bonds(F>O>N).

CH3NH2 - Got hydrogen bonds. Because of the electronegativity of the N.

HOCl - Got hydrogen bonds. The same reason, about the O.

NCl3 - Not got hydrogen bonds. It's a covalentic compound and every covalentic compound got only VDV(Van Der Vals) bonds or covalentic bonds.

NH4Br - Got hydrogen bonds. Because of electronegativity of the N; And also the electronegativity of the Br(2.8) is lower than the N(3.0), N can able to use 5 bonds.
__________________
Today is a good day to die...
Tomorrow is even better...
kafukai is offline   Reply With Quote
Old 11-01-2008, 02:15 AM   #1013
Hunter-nin
 
DeathGuiseX's Avatar


Join Date: Feb 2005
Location: East Side, NERV
Posts: 2,390
My Mood:
Rep Power: 31
DeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond repute
Send a message via AIM to DeathGuiseX
Default Re: Homework Help v1.3

Yay! More math.
Evaluate int (cosx + sinx)^2 dx <<----for this, I expanded it and made separated it into three integrals, but I don't know what to do from there.
For what value of k > 0, does int (4kx-5k)dx = k^2 <---I have no idea for this, but I'm trying atm.
__________________
DeathGuiseX is offline   Reply With Quote
Old 11-01-2008, 06:39 AM   #1014
Genin


Join Date: Oct 2005
Posts: 75
Rep Power: 0
ahme has much to be proud ofahme has much to be proud ofahme has much to be proud of

Basic Bronze 
Total Awards: 1

Default Re: Homework Help v1.3

The first question:
(cos x + sin x) = cos^2 x + 2 cos x sin x + sin^2 x
Whenever there is sin^2 x or cos^2 x, check if anything can be simplified. Here we have cos^2 x + sin^2 x = 1.
(cos x + sin x)^2 = 1 + 2 cos x sin x
The one can be easily integrated.
2 cos x sin x
Again whenever you have a multiplication of two functions check if one is the derivative of the other or the derivative multiplied by a constant. Luckily, we have sin x and cos x. The cos x is the derivative of sin x. So make the substitution u = sin x. Note: you could also have made the substitution u = cos x since the derivative of cos x = - sin x). Now, everything should be easily integrated.

Also, if you are good in trigonometry, you may notice that 2 cos x sin x = sin 2x and you know that integral of sin 2x dx = -½ cos 2x + C
ahme is offline   Reply With Quote
Old 11-01-2008, 06:51 AM   #1015
Genin


Join Date: Oct 2005
Posts: 75
Rep Power: 0
ahme has much to be proud ofahme has much to be proud ofahme has much to be proud of

Basic Bronze 
Total Awards: 1

Default Re: Homework Help v1.3

Regarding the second question, aren't you missing any more details in the question? Something like the limits of the integral.
ahme is offline   Reply With Quote
Old 11-01-2008, 11:39 AM   #1016
ANBU
 
Magnum's Avatar


Join Date: Aug 2007
Location: Have to ask my mom
Posts: 1,925
My Mood:
Rep Power: 10
Magnum is a glorious beacon of light

Basic Gold 
Total Awards: 1

Default Re: Homework Help v1.3

I need to write a speech on these 2 topics(3mins each) and I need it real fast before 12:00pm:(.
Pls help
1.Generation gap
2.What is your role in saving the ailing planet.
Or u can at least tell me a good site for speeches
your help will be greatly appreciated.
__________________
Magnum is offline   Reply With Quote
Old 11-01-2008, 12:25 PM   #1017
Hunter-nin
 
DeathGuiseX's Avatar


Join Date: Feb 2005
Location: East Side, NERV
Posts: 2,390
My Mood:
Rep Power: 31
DeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond reputeDeathGuiseX has a reputation beyond repute
Send a message via AIM to DeathGuiseX
Default Re: Homework Help v1.3

Quote:
Originally Posted by ahme View Post
Regarding the second question, aren't you missing any more details in the question? Something like the limits of the integral.
Nope, thats all they give in the question. I'll find it out today, don't worry. Thanks for the help on the first one thou.
__________________
DeathGuiseX is offline   Reply With Quote
Old 11-01-2008, 01:46 PM   #1018
Medical-nin
 
gaara of the desert's Avatar


Join Date: Sep 2004
Location: the belgian desert
Posts: 718
My Mood:
Rep Power: 17
gaara of the desert is a jewel in the rough
Default Re: Homework Help v1.3

This has been a while but I'm quite sure, since k is a value, not a variable:

int (4kx-5k)dx = 4k int (x dx) -5k int (dx)= 4k*1/2 x^2-5kx

2kx^2 -5kx=k^2
2kx^2-5kx-k^2=0 (*)

that's true for x= [5k+-(25k^2 -4*2k*-k^2)^1/2] / (4k)

(in a formula like ax^2+bx+c=0 it is x= [-b+- (b^2-4ac)^1/2]/2a)

=[5k+-(33k)]/4k

=-7 or 38/4

fill these in as x in (*) and see what k is.
__________________


Roses are red
The ground is now too
Because it rained blood
From my Sabaku kyu
gaara of the desert is offline   Reply With Quote
Old 21-01-2008, 05:33 AM   #1019
Niju Shōtai
 
GiantMidget's Avatar


Join Date: Jan 2007
Location: New York,Brooklyn
Posts: 5,004
My Mood:
Rep Power: 16
GiantMidget is a name known to all
Default Re: Homework Help v1.3

I need help with my physics homework, the question is

A pelican is flying along a horizaontal path drops a fish from a height of 5.2m.the fish travels 9.3m horizontally before it hits the water below.

The acceleration is 9.81m/s

a)What was the pelicans intial speed

b)if the pelican was traveling at the same speed,but was only 3.6m above the water, how far would the fish have to travel horizontally before hitting the water below
__________________

Last edited by GiantMidget; 21-01-2008 at 05:42 AM.
GiantMidget is online now   Reply With Quote
Old 21-01-2008, 07:28 AM   #1020
Administrator
 
o({})o's Avatar


Join Date: Sep 2004
Location: Yuritopia!
Posts: 2,895
My Mood:
Rep Power: 666
o({})o has a reputation beyond reputeo({})o has a reputation beyond reputeo({})o has a reputation beyond reputeo({})o has a reputation beyond reputeo({})o has a reputation beyond reputeo({})o has a reputation beyond reputeo({})o has a reputation beyond reputeo({})o has a reputation beyond repute

Basic Bronze Basic Bronze Basic Gold Intermediate Silver Award Basic Gold 
Total Awards: 5

Send a message via ICQ to o({})o Send a message via Yahoo to o({})o
Default Re: Homework Help v1.3

Quote:
Originally Posted by GiantMidget View Post
I need help with my physics homework, the question is

A pelican is flying along a horizaontal path drops a fish from a height of 5.2m.the fish travels 9.3m horizontally before it hits the water below.

The acceleration is 9.81m/s

a)What was the pelicans intial speed

b)if the pelican was traveling at the same speed,but was only 3.6m above the water, how far would the fish have to travel horizontally before hitting the water below
Please keep in mind that I am not claiming to be good at physics.

I'm assuming that you aren't to take drag into account.

ay = 9.81
vy = v0 + 9.81t (We can assume the initial vertical acceleration was 0, so v0 can be ignored.)
dy = 4.905t2

You find these equations by integrating: a = vertical acceleration, v = vertical velocity, d = vertical displacement, t = # of seconds since release.

So, vertical position is...

5.2 - 4.905t2

However, we know that this vertical position should be 0 when it hits the water...

5.2 - 4.905t2 = 0
-4.905t2 = -5.2
t2 = 5.2 / 4.905
t = √(5.2 / 4.905)

Thus, √(5.2 / 4.905) seconds pass before the fish hits the water.

If it traveled 9.3m in that time, we have a horizontal displacement calculated as follows...

(Note that this assumes the bird's velocity is constant)

d = 9.3 = v0 * t + (a / 2) * t2
9.3 = v0 * √(5.2 / 4.905) + (0 / 2) * (√(5.2 / 4.905))2 (We use a = 0 since we assumed the bird's velocity was constant, hence no acceleration.)
9.3 = v0 * √(5.2 / 4.905) + 0
9.3 / √(5.2 / 4.905) = v0
dy = 9.3 / √(5.2 / 4.905) * t

Thus...

vx = 9.3 / √(5.2 / 4.905)
ax = 0

Now we've answered part a by finding vx. Part b is fairly similar but uses the information we just found to go in reverse.
__________________
Yuri FTW! - Created by: gooserapids
o({})o is offline   Reply With Quote
Reply

Thread Tools

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump