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Old 09-04-2008, 05:41 AM   #1141
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Default Re: Homework Help v1.3

I'm confused on this but,
where do I find the latin names of animals (and common names)?
Like, for my situation, I need to know the latin names of tapirs, horses, and rhinoceros.
(Is it just genus and species?, or am I off).

Edit: Lol i just realized what they were. Wow
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Old 09-04-2008, 06:08 AM   #1142
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Default Re: Homework Help v1.3

Quote:
Originally Posted by Dendra View Post
Um, a) you confused me even more, well sort of i'll explain below b) i didn't disrespect anybody, i was panicking to find an answer and i was afraid nobody would see my post. My mistake...sorry c) my teacher never went against me, I don't know where you got siding from..? When he explains it i get it, but after i get confused again. and I pay attention in class, or else i wouldn't know anything at all. Its simply y=mx+b. What dking wrote was what I learned in class. I told you I'm not good in math. All i wanted to know was what you would subtract 3/2 from. 4 and 3 right? 4=(3/2)3+y

Also, if my teacher gave me a graph, without any points, and i chose 4 coordinates, would it be the same answer? Even if it had a negative in it. And, up above where I wrote 4=(3/2)3+y . Would I divide 3/2? Then use that answer as slope? Or leave it as a fraction, I always get confused on my tests about that. Also, if i had a graph and the line crossed through the y-int, wouldn't i just use that? Do i have to subtract y and x from each other? This is so confusing..god.

edit- and in your final solution, how come theres no slope? And no y?
You clearly didn't read what I typed. I went step-by-step. It may simply be that your level of basic math comprehension is too low to function in the level you are at now. If you can't look at (3/2)3 and know that it is (3/2) * 3, then you need to bone up on your extreme basics. Either way, it is a moot point. "4=(3/2)3+y" is in no way a partof this problem. Go back, read my post 5 more times, and see if you can't answer some of your own questions then.

The methods in my post work for all situations you are going to encounter. 2 points is the minimum you would need to find the equation of a line. You might instead by given a slope and a single point. 4 points is no problem and works the same way that 2 does. In fact, all you do is pick 2 of the 4 to work with.

There is no slope written out because I have a slope of 1. When I multiply by 1, I don't need to write it. I actually explained that in my post, if you read it all.

You are annoying, and unlike in my profession, I'm not being paid to talk to you. Nor, for that matter, is anyone else on this forum. Don't post here again until you've worked through the problem I offered you in my previous reply. If you have it down on paper, and still can't follow it after applying what everyone else in this thread has already said, then I'd suggest that you speak to your teacher about getting extra help in person. You clearly need a tutor to go back through the basics with you, and I really can't stress that enough.
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Old 09-04-2008, 06:11 AM   #1143
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Default Re: Homework Help v1.3

Azn try this site it might have what your looking for Latin Names Searchable - Animals Insects Plants

im not sure if it has every animal but it has a lot.
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Old 09-04-2008, 01:53 PM   #1144
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Default Re: Homework Help v1.3

Quote:
Originally Posted by o({})o View Post
You clearly didn't read what I typed. I went step-by-step. It may simply be that your level of basic math comprehension is too low to function in the level you are at now. If you can't look at (3/2)3 and know that it is (3/2) * 3, then you need to bone up on your extreme basics. Either way, it is a moot point. "4=(3/2)3+y" is in no way a partof this problem. Go back, read my post 5 more times, and see if you can't answer some of your own questions then.

The methods in my post work for all situations you are going to encounter. 2 points is the minimum you would need to find the equation of a line. You might instead by given a slope and a single point. 4 points is no problem and works the same way that 2 does. In fact, all you do is pick 2 of the 4 to work with.

There is no slope written out because I have a slope of 1. When I multiply by 1, I don't need to write it. I actually explained that in my post, if you read it all.

You are annoying, and unlike in my profession, I'm not being paid to talk to you. Nor, for that matter, is anyone else on this forum. Don't post here again until you've worked through the problem I offered you in my previous reply. If you have it down on paper, and still can't follow it after applying what everyone else in this thread has already said, then I'd suggest that you speak to your teacher about getting extra help in person. You clearly need a tutor to go back through the basics with you, and I really can't stress that enough.
In your profession? They allowed you to become a teacher? Wow, with the way you talk I'm surprised they even gave you a license. Cleary after reading your previous posts, Miyah clearly said "She didn't know where to put the thread", and you thought that was disrespect. You might want to double-check what disrespect is in the dictionary. Funny how little things such as double posting is considered spamming yet being rude, offensive isn't. I don't care if your an administrator you have no right to talk to her like that. You make it sound likes she on her knees begging for YOUR help. Other users answered her question perfectly and simple, if she felt your method was hard, then its not cause shes stupid, its because your stupid. I don't care if i get warnings or banned or whatever, if i do, then I'll know its because I'm saying the truth.

Miyah, look chicklette, heres a step.

Its y=mx+b isnt it? So its like what we did when i came over. For the time switch y to the other side, and see, m mulitiplied by x and added with b has to equal y. Thats what you do. I'll send it in an email too seeing this may be considered as "spam".

Choosing any points properly shouldn't change the answer.

Stay away from negatives, I know you have trouble with that. But if you come across that on the performance task then member, your adding hot/taking hot away. Your adding cold, or your taking cold away.

If the line is straight then its undefined, in that case slope is zero.

There we go.
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Old 09-04-2008, 03:12 PM   #1145
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Default Re: Homework Help v1.3

Quote:
Originally Posted by Chicka21 View Post
In your profession? They allowed you to become a teacher? Wow, with the way you talk I'm surprised they even gave you a license. Cleary after reading your previous posts, Miyah clearly said "She didn't know where to put the thread", and you thought that was disrespect. You might want to double-check what disrespect is in the dictionary. Funny how little things such as double posting is considered spamming yet being rude, offensive isn't. I don't care if your an administrator you have no right to talk to her like that. You make it sound likes she on her knees begging for YOUR help. Other users answered her question perfectly and simple, if she felt your method was hard, then its not cause shes stupid, its because your stupid. I don't care if i get warnings or banned or whatever, if i do, then I'll know its because I'm saying the truth.
actually you'll get banned for being a dupe account ...you do know that mods/smods/admins know that you and the other broad are the same person, right?

I'm bored and troll feeding seems to pass the time.
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Old 09-04-2008, 11:16 PM   #1146
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Default Re: Homework Help v1.3

Quote:
Originally Posted by Chicka21 View Post
In your profession? They allowed you to become a teacher? Wow, with the way you talk I'm surprised they even gave you a license. Cleary after reading your previous posts, Miyah clearly said "She didn't know where to put the thread", and you thought that was disrespect. You might want to double-check what disrespect is in the dictionary. Funny how little things such as double posting is considered spamming yet being rude, offensive isn't. I don't care if your an administrator you have no right to talk to her like that. You make it sound likes she on her knees begging for YOUR help. Other users answered her question perfectly and simple, if she felt your method was hard, then its not cause shes stupid...
Let me preface with the same thing that I said to your other account: You are annoying. Let me now add: You are a moron.

You'll have to pardon me for knowing more about math education than you do. You'll also have to excuse that I offered help when you were clearly in need of it. I did not call you stupid until just now when you decided that it would be wise to demean someone who went out of their way to do you a favor. Instead of me looking up disrespect, it might be a better use of our collective time for you to look up selfish. Hopefully you will be able to identify one or two of your primary character flaws then.

Not that any further justification is needed, but you should know as well that my post was made out of concern because it was clear that you did not understand the explanations of the people who replied prior to my response.

Quote:
Originally Posted by Chicka21 View Post
its because your stupid. I don't care if i get warnings or banned or whatever, if i do, then I'll know its because I'm saying the truth.
Aside from being one of the most childish responses that I have ever seen on this forum, I'd also say this is among the dumbest. You are claiming to be unthreatened by my actions against you (trying to make yourself a martyr). However, the only reason you're not concerned is because you're not posting under your primary account right now. With everyone becoming aware of that, your credibility (as well as any public opinion based restriction preventing me from banning you) is completely dissolved. However, even if that wasn’t the case, I’m not out to win any PR contests here. I’d ban you just for telling me that I’m stupid after all the shit you pulled while spamming the Debates forum…

For basic amusement, I’m going to ban your dupe account. I’ll be waiting on the edge of my seat to see your original account’s response.

Quote:
Originally Posted by Chicka21 View Post
Miyah, look chicklette, heres a step.

Its y=mx+b isnt it? So its like what we did when i came over. For the time switch y to the other side, and see, m mulitiplied by x and added with b has to equal y. Thats what you do. I'll send it in an email too seeing this may be considered as "spam".

Choosing any points properly shouldn't change the answer.

Stay away from negatives, I know you have trouble with that. But if you come across that on the performance task then member, your adding hot/taking hot away. Your adding cold, or your taking cold away.
Trying to give yourself meaningless math advice makes you look even dumber than making dupe accounts did.

Quote:
Originally Posted by Chicka21 View Post
If the line is straight then its undefined, in that case slope is zero.

There we go.
All lines that you have seen and know how to graph are straight. The slope of a vertical line is undefined. The slope of a horizontal line is 0.
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Old 10-04-2008, 12:38 AM   #1147
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Default Re: Homework Help v1.3

You do realize Chicka21 is Meagan, and Dendra (me) is Miyah. My computer, even if i tried, (and i'll admit I've tried to make another account because it gave me trouble at first) would not even ALLOW me to make another account, we have to use a different internet. The IP's are the same because a) she made an account at my house on internet explorer b) i have a wi-fi and c) shes always at my house, while i use the computer, she uses my LP and d)how can i answer MY OWN question. As "chidlish" as I am. I would NEVER have the guts to say what she said. Despite that i'm over a computer.

But she did help me out, because everything that I asked for help, was on my performance today. So i now know how to solve for y=mx+b. So now i have another "stupid" question. Its proportions, and similar triangles.

1- How do you solve for a triple proportion. Which would look like 2/3=x/4=5/8. Flip it horizontally. I know you have to divide The first two denominators, then mulitiply the answer by the numerator. But i only know how to do that for two equations not three.

2- Which brings me to similiar triangles. My math teacher, he gave us a review and a question he said is guarnteed to come up is similar triangles. Basically he gives us two traingles triangle A has all its sides labelled. ex. 7m, 2m, 5m. And then triangle B would only have 2 sides labelled. ex. 4m, 6m. How do you find the third angle? I asked him if i use pythagorean and he said no, because you can only do that for right-angle triangles. So he said you have to use proportions. How would i find that out?
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Old 10-04-2008, 05:55 AM   #1148
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Default Re: Homework Help v1.3

Quote:
Originally Posted by Dendra View Post
You do realize Chicka21 is Meagan, and Dendra (me) is Miyah. My computer, even if i tried, (and i'll admit I've tried to make another account because it gave me trouble at first) would not even ALLOW me to make another account, we have to use a different internet. The IP's are the same because a) she made an account at my house on internet explorer b) i have a wi-fi and c) shes always at my house, while i use the computer, she uses my LP and d)how can i answer MY OWN question. As "chidlish" as I am. I would NEVER have the guts to say what she said. Despite that i'm over a computer.
Sorry, but I don't really believe you. You both type in the same manner, and you have the same IP. What's more, you were both talking to each other in the intro forum in a thread... but "she" was on your PC at the time? Why would you talk in a thread if you are standing right next to each other and trading off the computer just to type?

Also "she" didn't answer your question. "She" told you things that aren't true or have no value in solving the problem. Or, I should say, "she" at least posted things that were nonsensical. What "she" said to you in person is another matter.



Quote:
Originally Posted by Dendra View Post
But she did help me out, because everything that I asked for help, was on my performance today. So i now know how to solve for y=mx+b. So now i have another "stupid" question. Its proportions, and similar triangles.
I'm still not sure how the info in her previous post could help anyone at all. Perhaps your problem up to this point is explained, in part, by your reliance on false information coming from your friends who think that they are doing you a favor by "teaching?"



Quote:
Originally Posted by Dendra View Post
1- How do you solve for a triple proportion. Which would look like 2/3=x/4=5/8. Flip it horizontally. I know you have to divide The first two denominators, then mulitiply the answer by the numerator. But i only know how to do that for two equations not three.
2 / 3 = x / 4 = 5 / 8 is not a "triple" proportion. For that matter, it's nothing at all. It's an equation that isn't true. A proportion relates one value (which is usually measured in one type of unit) to another value (which is typically measured in another type of unit). However, they could just be values... I assume that is what you are working with based on the level presented in this "example" that you came up with.

Try 2 / 3 = x / 4 = 4 / 6 instead... Not exactly the easiest example to start with, but at least it works.



Quote:
Originally Posted by Dendra View Post
2- Which brings me to similiar triangles. My math teacher, he gave us a review and a question he said is guarnteed to come up is similar triangles. Basically he gives us two traingles triangle A has all its sides labelled. ex. 7m, 2m, 5m. And then triangle B would only have 2 sides labelled. ex. 4m, 6m. How do you find the third angle? I asked him if i use pythagorean and he said no, because you can only do that for right-angle triangles. So he said you have to use proportions. How would i find that out?
Did he tell you that all the angles are the same (or at least 2 of the angles are the same)? I assume that you are looking to find the third side (not angle). Assuming the angles are the same, then we are looking at similar triangles. Similar triangles have all their sides in an equal proportion. Once again, your example makes no sense because there is no way to get equal proportions with the numbers you provided. Try getting an example from the book next time (protip: Your textbook was written by people who probably do know a bit about math).



I'd like to stress that this is the HW thread and not the life lessons thread.

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Old 11-04-2008, 04:13 PM   #1149
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Default Re: Homework Help v1.3

Modify the pointer-based implementation of the ADT queue Your queue class should have just one member variable - a pointer to the node at the back of the queue. In the copy constructor, use existing member functions—just as the destructor uses dequeue and isEmpty—to make your code concise and clear, and to avoid duplication.

Here's the pseudo.

/** @file QueueP.h*/

#include "QueueException.h"
and any other includes.

typedef desired-type-of-queue-item ueueItemType;

/* ADT queue - pointer-based implementation. */

class Queue
{
public
// constructors and destructor:

/**default constructor. */
Queue();

/** copy constructor .
* @ param Q the Queue to copy. */
Queue (const Queue& Q);

/** Destructor. */
~Queue();

//Queue operations:

/** Determines whether this is queue is empty.
*@ pre None.
@post none.
@return true if this queue is empty; otherwise returns false. */

bool isEmpty() const;

-inserts an item at the back of this queue.
-@pre newItem is the item to be inserted.
-@post if the insertion is successful, newItem is at the back of this queue.
-@throw QueueException if memory allocation fails. */


void enqueue (const QueueItemType& newItem) throw (QueueException);

/*

0 Dequeues the front of this queue.
-@pre none
-@ post i this queue is not empty, the item that was added to this quue earliest is deleted.
- @throw QueueException if this queue is empty. */

void dequeue() throw (QueueException);

/**

retreieves and deletes the front of this queue.
-@pre none
-@post if this queue is not empty, queue front contains the item that was added to this queque earliest, and the item is deleted
-@ throw QueueExcption if this queue is empty. */

void dequeue(QueueItemTypes& queueFront) throw(QueueException);

/* retrieves the item at the front of a queue.
-@pre none
-@pro if this queue is not empty, queueFront contains the item that was added to this queue earliest.
-@throw queueException if this queue is empty. */

void getFront (QueueItemType& queueFront) const throw(QueueExeption);


private
/* the queue is implemented as a linked list with one external pointer to the front of the queue and a second external pointer to the back of the queue. */

struct QueueNode
{

QueueItemType item;
QueuenNode *next;
}; //end Queue
//End of header file.

all include files here.

using namespace std;

Queue:: Queue() : backPtr(NULL), frontPtr(NULL)
{
} //end default constructor

Queue:: Queue(const Queue& Q)
{
} // end copy constructor

Queue::~Queue()
{

while(!isEmpty()
dequeue();

assert((backPtr==NULL) && (fontPtr ==NULL));
} //end destructor

bool Queue::isEmpty() const
{
return backPtr == NULL;
} //end isEmpty function

void Queue:: enqueue (const QueueitemType& newItem) throw (QueueException)
{
try
{// create a new node
QueueNode *newPtr = new QueueNode;

//set data portion of new node
newPtr -> item = newItem;
newPtr -> next = NULL;

//insert the new node

if (isEmpty()
// insertion into empty queue
frontPtr=newPtr;

else
// insertion into nonempty queue
backPtr ->next = newPtr;

backPtr = newPtr; //new node is at back
}

catch (bad_alloc e)
{
throw QueueException( "QueueException: enque cannot allocate memory." );
} //end try

}// end enqueue


.

.
.
.
.
etc

I'm really stuck at how to modify this into a circular linked list, how do you know if it's the first and back?
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Old 14-04-2008, 02:24 AM   #1150
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Default Re: Homework Help v1.3

Were you expressly told to use a circular list? There isn't normally any need with a queue, you just keep a normal linked list with a pointer to front and back.
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Old 14-04-2008, 03:17 AM   #1151
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Default Re: Homework Help v1.3

Quote:
Originally Posted by o({})o View Post
Sorry, but I don't really believe you. You both type in the same manner, and you have the same IP. What's more, you were both talking to each other in the intro forum in a thread... but "she" was on your PC at the time? Why would you talk in a thread if you are standing right next to each other and trading off the computer just to type?

Also "she" didn't answer your question. "She" told you things that aren't true or have no value in solving the problem. Or, I should say, "she" at least posted things that were nonsensical. What "she" said to you in person is another matter.





I'm still not sure how the info in her previous post could help anyone at all. Perhaps your problem up to this point is explained, in part, by your reliance on false information coming from your friends who think that they are doing you a favor by "teaching?"





2 / 3 = x / 4 = 5 / 8 is not a "triple" proportion. For that matter, it's nothing at all. It's an equation that isn't true. A proportion relates one value (which is usually measured in one type of unit) to another value (which is typically measured in another type of unit). However, they could just be values... I assume that is what you are working with based on the level presented in this "example" that you came up with.

Try 2 / 3 = x / 4 = 4 / 6 instead... Not exactly the easiest example to start with, but at least it works.





Did he tell you that all the angles are the same (or at least 2 of the angles are the same)? I assume that you are looking to find the third side (not angle). Assuming the angles are the same, then we are looking at similar triangles. Similar triangles have all their sides in an equal proportion. Once again, your example makes no sense because there is no way to get equal proportions with the numbers you provided. Try getting an example from the book next time (protip: Your textbook was written by people who probably do know a bit about math).



I'd like to stress that this is the HW thread and not the life lessons thread.

No lol, we don't type in the same manner. A) She sucks at grammar B) Her answer was correct, i did it on my exam and my teacher said yes thats right but i have to put in in y=mx+b format. and C) When I said shes always at my house, i literally meant it, shes staying with me .During the intro thread she was upstairs using my LT and i was down here. Anywho, doesn't matter lol, i know whats true and whats not, But anyways back to hw help. Lessons aren't my point, its just questions, I am NOT good in explaining math questions, it kinda sorta shows.

1- Because i've been away all week I wasn't able to see your reply earlier so i asked my teacher and he said to block one of the proportion questions solve or x or y then you'll have the other answer.

2- I don't know, i just randomly made that equation up, it shows lol. But i got my answer, and yeah he told me all angles are the same.

3- Moving on to my next question. Is there anyone here good in academic Science (gr.10) Or if your good;I assume you don't know science because you said you don't know Physics (?). I thought Chemistry would be easy, but i was hit hard. I'll begin with whats a Lewis Dot diagram, Bohr and Bohr-Rutherford Diagram, and hook diagram for elements and stuff. I don't get it. Why do you take some charges away while others you don't? Such as Krypton, you don't add or subtract charges. When I say charges I mean those little numbers in the corner, such as +2 and -3. I know its to balance, but how do you bond, and draw them. Especially for two elements. ie he put Tin and Phosphate together, and asked to draw a bohr-rutherford.
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Old 14-04-2008, 04:48 AM   #1152
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Default Re: Homework Help v1.3

^ A person asking strangers for free help should have a better attitude about it.

People seem to have an increasingly bizarre sense of entitlement these days...
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Old 14-04-2008, 06:00 AM   #1153
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Default Re: Homework Help v1.3

Anybody know art terms?

What does it mean by
-sense of transparency
- sense of density
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Old 14-04-2008, 06:00 AM   #1154
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Default Re: Homework Help v1.3

Yeah, I was told to use a Circular linked list.
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Old 14-04-2008, 07:13 AM   #1155
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Default Re: Homework Help v1.3

Another art related question

Find out the dimensions to Giotto's Crucifixion and where it is currently

When putting in the works cited page, if there are 3 copyright years, do you put all 3 years or the most recent one?

Last edited by Kigga; 14-04-2008 at 08:27 AM.
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Old 14-04-2008, 08:58 AM   #1156
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